#9 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Black R9=8 variationOutcome: Advantage to Red!
1. C2=5 C8=5 2. H2+3 …………
Red developed his right 's horse.
2. ………… H8+7
Black also developed his left's horse.
3. R1=2 …………
Red plays R1=2 for Filed Chariot, which is more popular than R1+1.
Based on games statistic, Red R1=2 has a higher winning rate if compared with R1+1.This might be the reason why R1=2 is more popular than R1+1.
Red also could play R1+1 for Ranked Chariot, however this is out of our discussion in this chapter.
3. ………… R9=8
Since Red R1=2 has a higher winning rate, could Black trade his left chariot with Red's filed chariot? This is a common question has been asked by several Xiangqi beginners.
4. R2+9 …………
Of course, Red would happy to trade his chariot.
4. ………… H7-8
Now let review the board situation after pieces exchanged.
Current Board Status Analysis:
Let us count the number of valid moves for each player.
1) Red had develop his right cannon C2=5 and right horse H2+3. Therefore, there are total two valid move for Red.Also, Red move first in next move.
2) Although, Black had move his left's horse 2 times, however the mentioned horse still remains at initial position.Therefore, the horse's moves were not valid.So, the only valid move for Black was the central cannon C8=5.
3) Obviously, Red has the higher valid moves if compared with Black.We can concluded that Red is in better position if compared with Black.
Obviously Black R9=8 is not a good move. Red has gained higher valid moves, advantage to Red.The correct move for Black would be R1+1 in ply #3.