#40 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Black P3+1 then E3+1

 #40 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Black P3+1 then E3+1

Outcome: Advantage go to Red

  1. C2=5  C8=5    2. H2+3  H8+7
  3. R1=2  R9+1    4. P3+1  R9=4
  5. H8+7  P3+1

We had discussed Black R4+3 R4+4, R4+5 and R4+7, advantages all go to Red.

In this post, we will start to discuss Black P3+1.

As mentioned earlier, the most efficient move Black would be H2+3 for proper horse.

Now Black plays P3+1, is to prevent Red to develop left horse. In this case, what is the most efficient move for Red?




  6. R2+5  …………

Correct move!

Black pawn became the target for Red!

In general, there are 3 main variations for Black.
1) E3+1
2) H2+3
3) C5-1

In this post, we will discuss E3+1 variation.

  6. …………  E3+1    7. C8=9  …………

Red C8=9 is a good move. Red should not C8+4, Black could R4+2.

Now is Black's turn. There are 3 main variations.

1) C2+2
2) H2+3
3) R4+2

In this post we discuss C2+2

  7. …………  C2+2

Black wants to chase away Red Chariot.

  8. R2+1

However, Red change his mind to attack Black left horse.

Current board status analysis:
1) Black left horse is under attack, Black need to find solution for it

2)Red has develope most of his main pieces.

Outcome: Advantage go to Red