#42 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Black P3+1, E3+1 then R4+2

 #42 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Black P3+1, E3+1 then R4+2

Outcome: Advantage go to Red

  1. C2=5  C8=5    2. H2+3  H8+7
  3. R1=2  R9+1    4. P3+1  R9=4
  5. H8+7  P3+1

We had discussed Black R4+3 R4+4, R4+5 and R4+7, advantages all go to Red.

In this post, we will start to discuss Black P3+1.

As mentioned earlier, the most efficient move Black would be H2+3 for proper horse.

Now Black plays P3+1, is to prevent Red to develop left horse. In this case, what is the most efficient move for Red?


  6. R2+5  …………

Correct move!

Black pawn became the target for Red!

In general, there are 3 main variations for Black.
1) E3+1
2) H2+3
3) C5-1

In this post, we will discuss H2+3 variation.


  6. …………  E3+1    7. C8=9  …………

Red C8=9 is a good move. Red should not C8+4, Black could R4+2.

Now is Black's turn. There are 3 main variations.

1) C2+2
2) H2+3
3) R4+2

We had discussed the variations C2+2 and H2+3.

In this post we discuss R4+2

  7. …………  R4+2

Black R4+2 to protect edge pawn and prevent Red C9+4.

So, what is the effective move for Red? 



  8. R9=8  …………

Of course Red R9=8 to develop his chariot.

  8. …………  H2+4    9. C5=6  …………

Good move! Red plan to exchange his cannon with Black's horse for material gain.

  9. …………  C2=3   10. C6+6  …………

Good move. A continue move to force Black's chariot move back.

 10. …………  R4-2   11. C9+4  …………

Since Black's edge pawn is no more protected.

 11. …………  R1=3   12. C9=7  C3=4
 13. C7=3  E7+9   14. E7+5

Red E7+5 is to prevent Red P3+1.

Current board situation:
1) Red both chariots are on strategic positions

2) Black both elephants are not in good formation

Outcome: Advantage go to Red