#41 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Black P3+1 then E3+1 follow by H2+3
Outcome: Advantage go to Red
1. C2=5 C8=5 2. H2+3 H8+7
3. R1=2 R9+1 4. P3+1 R9=4
5. H8+7 P3+1
We had discussed Black R4+3 R4+4, R4+5 and R4+7, advantages all go to Red.
In this post, we will start to discuss Black P3+1.
As mentioned earlier, the most efficient move Black would be H2+3 for proper horse.
Now Black plays P3+1, is to prevent Red to develop left horse. In this case, what is the most efficient move for Red?
6. R2+5 …………
Correct move!
Black pawn became the target for Red!
In general, there are 3 main variations for Black.
1) E3+1
2) H2+3
3) C5-1
In this post, we will discuss E3+1 variation.
6. ………… E3+1 7. C8=9 …………
Red C8=9 is a good move. Red should not C8+4, Black could R4+2.
Now is Black's turn. There are 3 main variations.
1) C2+2
2) H2+3
3) R4+2
In this post we discuss H2+3
7. ………… H2+3
Black develops his right horse.
Therefore, what is the most effective move for Red?
8. C9+4 …………
Corrent move!
8. ………… R1=2 9. C9=8 R2=3
10. C8=3 E7+9 11. R2=4 …………
This is the correct move for Red. If Red played R9=8 to develop his chariot, then Black could C2+2, R2+1, Black R4+4. Black gains some advantages.
11. ………… C2+2 12. R4+2
Current board situation:
1) Red chariot is capturing Black's cannon and horse.Red will gain material.
Outcome: Advantage goto Red
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