#21 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Red H8+7, Black R9=3 then H2+3

#21 Same Direction Cannon Double Headed Snake Pawn Formation vs Double Ranked Chariot - Red H8+7, Black R9=3 then H2+3

Outcome: Advantage to Red

  1. C2=5  C8=5    2. H2+3  H8+7    3. R1=2  R9+1    4. H8+7  P3+1
  5. P3+1  R9=3    6. E7+9  C2+4    7. A6+5  P3+1    8. P7+1  R3+4
  9. R9=7  …………

In this situation, Black has 4 main variations.
1) R3=7
2) C5=3
3) H2+3
4) R3+1

In previous post, we had discussed Black R3=7, C5=3 and R3+1, all led to Red advantage.

In this chapter, we discuss Black H2+3 variation.

  9. …………  H2+3

In this variation, Black plays H2+3. What is the best move for Red?




 10. H7+8  …………

Correct move.

 10. …………  R3+4

Black forces to exchange the chariot. If Black played R3=7, Red would respond with R7+7.

If we do simple math calculation. Black's chariot has make 4 moves, whiereby Red's left chariot only make one move.Red has gained benefit by exchanging the chariot.

 11. E9-7  R1=2   12. H8+9  …………

Key move!

 12. …………  C2=3   13. H9+7  R2+7   14. H7-5  H7+5   15. C5+4  A4+5
 16. E3+5

Current board status analysis:

1) Red has additional 2 pawns, this is huge advantage.

2) Red has various main pieces, whereas Black only left chariot and cannon. Red can has higher combination of attack tactics.

Outcome: Advantage to Red.